A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 ~m ~s ⁻² . The fuel is finished in 1 ~min and it continues to move up. What is the maximum height reached?

Step-by-step solution

Height covered in 1 ~min , s₁=u t+ 1 2 a t^2=0+ 1 2 10 (60)^2=18000 ~m Velocity attained after 1 ~min , v=u+a t=0+10 60=600 ~m ~s ⁻¹ After the fuel is finished, u=600 ~m ~s ⁻¹, v=0 aligned & v^2-u^2=2 g s₂ & or 0-(600)^2=2 (-9.8) s₂ & or s₂= (600)^2 2 9.8 =18367.3 ~m aligned Maximum height reached =s₁+s₂=36367.3 ~m =36.4 ~km