AIIMS2019PhysicsCenter of Mass, Momentum and Collision
A gun applies a force F on a bullet which is given by F= (100-0.5 10^5 t ) N . The bullet emerges out with speed 400 ~m ~s ⁻¹ . Then find out the impulse exerted till force on bullet becomes zero
Options
- A0.2 ~N ~s
- B0.3 ~N ~s
- C0.1 ~N ~s
- D0.4 Ns
Correct answer
C. 0.1 ~N ~s
Step-by-step solution
aligned & (c) : Given, force F= (100-0.5 10^5 t ) N & 100-0.5 10^5 t=0,100=0.5 10^5 t( F=0) & t=2 10⁻³ sec & Impulse, I= F d t= ₀^ 2 10⁻³ (100-0.5 10^5 t ) d t & I= [100 t- 10^5 2 t^2 2 ]₀^ 2 10⁻³ & I= [100 2 10⁻³- 10^5 4 4 10⁻⁶ ] & I=10⁻¹=0.1 ~N ~s aligned