AIIMS2018PhysicsCenter of Mass, Momentum and Collision
Three bricks each of length L and mass M are arranged as shown from the wall. The distance of the centre of mass of the system from the wall is
Options
- AL / 4
- BL / 2
- C(3 / 2) L
- D(11 / 12) L
Correct answer
D. (11 / 12) L
Step-by-step solution
From figure, aligned & x₁= L 2 , x₂= L 2 + L 2 =L & and x₃= L 2 + L 4 + L 2 = 5 4 L & X_ C M = m₁ x₁+m₂ x₂+m₃ x₃ m₁+m₂+m₃ & = M L 2 +M L+M 5 L 4 M+M+M = 11 4 M L 3 M = 11 12 L aligned