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AIIMS2005PhysicsCenter of Mass, Momentum and Collision

In the figure given, the position-time graph of a particle of mass 0.1 ~kg is shown. The impulse at t=2 sec is

Options

  1. A0.2 ~kg ~m sec ⁻¹
  2. B-0.2 ~kg ~m sec ⁻¹
  3. C0.1 ~kg ~m sec ⁻¹
  4. D-0.4 ~kg ~m sec ⁻¹

Correct answer

A. 0.2 ~kg ~m sec ⁻¹

Step-by-step solution

Impulse = change in momentum =m v= m x t =0.1 4-0 2-0 =0.2 ~kg msec ⁻¹ .

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