Match List-I with List-II regarding the catalytic cycle of an enzyme action. List-I List-II A. Substrate binding I. Breaks chemical bonds of the substrate B. Induced fit II. Enzyme alters its shape to fit more tightly C. Active site action III. Free enzyme is ready to bind to another molecule D. End of cycle IV. Substrate fits into the active site Choose the correct answer from the options given below:

Step-by-step solution

According to the catalytic cycle of an enzyme action described in NCERT: First, the substrate binds to the active site of the enzyme, fitting into the active site (A-IV). The binding of the substrate induces the enzyme to alter its shape, fitting more tightly around the substrate, which is known as induced fit (B-II). The active site of the enzyme, now in close proximity to the substrate, breaks the chemical bonds of the substrate to form the enzyme-product complex (C-I). Finally, the enzyme releases the products,