NEETZoologyMolecular Basis of Inheritance
Match List-I with List-II. List-I List-II (A) Sigma factor (I) 5' end of hnRNA (B) Rho factor (II) 3' end of hnRNA (C) Capping (III) Initiation of transcription (D) Tailing (IV) Termination of transcription Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- B(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- C(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Correct answer
D. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Step-by-step solution
In bacteria, the RNA polymerase transiently binds to the initiation factor, sigma ( ), to initiate transcription, and to the termination factor, rho ( ), to terminate the process. In eukaryotes, the primary transcript (hnRNA) undergoes post-transcriptional modifications. During capping, an unusual nucleotide (methyl guanosine triphosphate) is added to the 5' end of hnRNA. In tailing, adenylate residues (poly-A tail) are added at the 3' end in a template-independent manner. Therefore, the correct match is (A)-(III),