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NEETZoologyMolecular Basis of Inheritance

Match List-I with List-II regarding the lac operon in E. coli . List-I List-II A. Presence of inducer I. Hydrolysis of lactose into galactose and glucose B. Absence of inducer II. Increases permeability of the cell to -galactosides C. y gene product III. Repressor binds to the operator region D. z gene product IV. Inactivates the repressor protein Choose the correct answer from the options given below:

Options

  1. AA-IV, B-III, C-II, D-I
  2. BA-III, B-IV, C-II, D-I
  3. CA-IV, B-III, C-I, D-II
  4. DA-III, B-IV, C-I, D-II

Correct answer

A. A-IV, B-III, C-II, D-I

Step-by-step solution

In the lac operon: A. Presence of inducer (lactose or allolactose) inactivates the repressor protein by binding to it, allowing RNA polymerase access to the promoter (A-IV). B. In the absence of an inducer, the active repressor binds to the operator region, preventing transcription of the structural genes (B-III). C. The y gene codes for permease, which increases the permeability of the cell to -galactosides (C-II). D. The z gene codes for -galactosidase, which is responsible for the hydrolysis of the disaccharide

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