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NEETZoologyPrinciples of Inheritance and Variation

In a genetic cross, the recombination frequencies between three linked genes A , B and C are as follows: Between A and B : 9 % Between A and C : 17 % Between B and C : 8 % Based on this data, what is the correct linear sequence of these genes on the chromosome?

Options

  1. AA-B-C
  2. BB-A-C
  3. CA-C-B
  4. DC-A-B

Correct answer

A. A-B-C

Step-by-step solution

Alfred Sturtevant used the frequency of recombination between gene pairs on the same chromosome as a measure of the distance between genes. 1 % recombination frequency is equal to 1 map unit. Given recombination frequencies: Distance between A and C = 17 map units Distance between A and B = 9 map units Distance between B and C = 8 map units The maximum distance is between genes A and C ( 17 map units), meaning they are located at the two ends of the sequence. The sum of the distances between A-B and B-C ( 9 + 8 = 1

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