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NEETZoologyPrinciples of Inheritance and Variation

Match List-I with List-II regarding the inheritance of Mendelian disorders. List-I (Parental Cross) List-II (Probability of an affected child) A. Normal homozygous female Colorblind male I. 0 B. Sickle-cell trait male Sickle-cell trait female II. 1/4 C. Heterozygous male for Myotonic dystrophy Normal female III. 1/2 D. Colorblind female Colorblind male IV. 1 Choose the correct answer from the options given below:

Options

  1. AA-IV, B-III, C-II, D-I
  2. BA-II, B-III, C-I, D-IV
  3. CA-I, B-III, C-II, D-IV
  4. DA-I, B-II, C-III, D-IV

Correct answer

D. A-I, B-II, C-III, D-IV

Step-by-step solution

Cross A: Color blindness is an X-linked recessive trait. A normal homozygous female ( X^C X^C ) and a colorblind male ( X^c Y ) will produce carrier daughters ( X^C X^c ) and normal sons ( X^C Y ). The probability of an affected child is 0 . Cross B: Sickle-cell anaemia is an autosomal recessive trait. A cross between two carriers ( Hb^A Hb^S Hb^A Hb^S ) produces affected offspring ( Hb^S Hb^S ) with a probability of 1/4 . Cross C: Myotonic dystrophy is an autosomal dominant trait. A heterozygous male ( Aa ) and a

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