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NEETZoologyPrinciples of Inheritance and Variation

A man with blood group A, whose father had blood group O, marries a woman with blood group AB. What is the probability that their child will have blood group B?

Options

  1. A0 %
  2. B50 %
  3. C75 %
  4. D25 %

Correct answer

D. 25 %

Step-by-step solution

The man has blood group A, but his father had blood group O (genotype ii ). Therefore, the man must have inherited an i allele from his father, making his genotype I^A i . The woman has blood group AB, so her genotype is I^A I^B . A cross between the man ( I^A i ) and the woman ( I^A I^B ) yields the following offspring genotypes: 1 4 I^A I^A (Blood group A) 1 4 I^A i (Blood group A) 1 4 I^A I^B (Blood group AB) 1 4 I^B i (Blood group B) Thus, the probability of them having a child with blood group B is 1 4 or 25 %

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