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NEET2009ZoologyPrinciples of Inheritance and VariationActual

Percentage of recombination between A and B is 9 %, ~A and C is 17 %, ~B and C is 26 % , then the arrangement of genes is

Options

  1. AABC
  2. BACB
  3. CBCA
  4. DBAC.

Correct answer

D. BAC.

Step-by-step solution

1 map unit or centimorgan is equivalent to 1 % recombination between two genes. The frequency of recombination can be used to depict the arrangement of the genes. Recombination frequency between three genes is aligned & A-B=9 % & A-C=17 % and & B-C=26 % aligned By manipulating the three possibilities of their arrangements A - B - C , A - C - B and B - A - C , it was found that the three gene must be arranged in the order B-A-C with distance between B-A being 9 cM and A - C being 17 cM and the distance between B - C

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