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NEET2011ZoologyPrinciples of Inheritance and VariationActual

A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the X-chromosome marries a normal man. How will the progeny be?

Options

  1. AAll sons and daughters are haemophilic and colourblind
  2. BHaemophilic and colourblind daughters
  3. C50 % haemophilic colourblind sons and 50 % haemophilic sons
  4. D50 % haemophilic daughters and 50 % colourblind daughters

Correct answer

C. 50 % haemophilic colourblind sons and 50 % haemophilic sons

Step-by-step solution

Haemophilia and colour blindness both are recessive X-linked traits. They express in males when present in single copy (heterozygous) but in females, they express only when present in homozygous condition. Results (a) 50 % sons are colourblind and haemophilic. (b) 50 % sons are haemophilic only. (c) 50 % daughters are carrier for colour blindness and haemophilia. (d) 50 % daughters are carrier for haemophilia only.

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