AP EAMCET202422 May 2024Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual
Two blocks of equal masses are tied with a light string passing over a massless pulley (Assuming frictionless surfaces) acceleration of centre of mass of the two blocks is (g=10 ~ms ⁻² )
Options
- A5( 3 -1) 2
- B5( 3 -1) 2 2
- C5( 3 +1) 2 2
- D5( 3 -1) 2
Correct answer
B. 5( 3 -1) 2 2
Step-by-step solution
The acceleration of the block is a= (5 3 -5) M (M+m) = 5 2 ( 3 -1) m / s Acceleration of centre of mass is a _ cm = m ₁ a ₁+ m ₂ a ₂ ~m ₁+ m ₂ = M ( a ₁+ a ₂ ) 2 M = a ₁+ a ₂ 2 Also, a ₁= a i , a ₂=a j aligned & a _ c m = a 2 ( i + j ) & a_ c m = a 2 2 = 1 2 5 2 ( 3 -1)= 5( 3 -1) 2 2 aligned