A particle of mass 10 ~g is moving towards east with a velocity of 10 ~ms ⁻¹ and another particle of mass 15 ~g is moving towards north with a velocity of 5 ~ms ⁻¹ . The magnitude of the velocity of the centre of mass of the system of the two particles is

Step-by-step solution

Mass, m ₁=10 ~g =10 10⁻³=10⁻² Kg velocity, v ₁=10 ~m / s Mass of 2nd particle, M₂=15 ~g =15 10⁻³ Kg Velocity of IInd particle, V₂=5 ~m / s centre of mass makes 45^ angle with north and east side. Hence velocity of centre of mass is given as: aligned & V_ 1 ~m = m ₁ v ₁ ₁+ m ₂ , ₁ ~m ₁+ m ₂ & = 10 10 45+15 5 45 10+15 & = 1 2 [ 175 25 ]= 7 2 ( 2 )=4.9 ~m / s ; 5 ~m / s aligned