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AP EAMCET20224 Jul 2022Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

A ball of mass 0 . 5 kg moving horizontally at 10 m s - 1 strikes a vertical wall and rebounds with speed v . The magnitude of the change in linear momentum is found to be 8 . 0 kg m s - 1 . The magnitude of v is,

Options

  1. A6 . 0   m   s - 1
  2. B9 . 0   m   s - 1
  3. C26 . 0   m   s - 1
  4. D13 . 0   m   s - 1

Correct answer

A. 6 . 0   m   s - 1

Step-by-step solution

Linear momentum is a vector quantity. Initial momentum = + m × 10   i ^ . Final momentum = - m v   i ^ Change in linear momentum = - 10 m   i ^ - m v   i ^ = - 10 + v m   i ^ Therefore, 10 + v × 0 . 5 = 8 ⇒ v = 16 - 10 = 6   m   s - 1

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