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AP EAMCET20224 Jul 2022Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

Masses m 1 3 N 1 N are placed at x = N , when N = 2 , 3 , 4 , … ∞ . If the total mass of the system is M , then the centre of mass is

Options

  1. A1 6 m M
  2. B1 5 m M
  3. C1 3 m M
  4. D1 2 m M

Correct answer

A. 1 6 m M

Step-by-step solution

The arrangement of masses will look as given below, Centre of the mass of the system along X-axis will be given as, X c m = m 1 x 1 + m 2 x 2 + . . . m 1 + m 2 + . . . = m 1 3 2 1 2 × 2 + m 1 3 3 1 3 × 3 + . . . M = m M × 1 3 2 + 1 3 3 + . . . = m M × 1 3 2 1 - 1 3 = m 6 M

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