AP EAMCET202124 Aug 2021Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual
The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is 12 amu and mass of oxygen atom is 16 amu. Calculate the position of the centre of mass of the carbon monoxide molecule.
Options
- A6.3 Å from the carbon atom
- B1.0 Å from the oxygen atom
- C0.63 Å from the carbon atom
- D0.12 Å from the oxygen atom
Correct answer
C. 0.63 Å from the carbon atom
Step-by-step solution
Given that, mass of oxygen, m_ O =16 amu Mass of carbon, m_ C =12 amu Distance between them, r=1.1 Å Let x be the distance of centre of mass from carbon atom By using expression of centre of mass for two particle system, X_ COM = m₁ x₁+m₂ x₂ m₁+m₂ Assuming centre of mass at orgin, we get X_ COM =0= m_ C (-x)+m_ O (r-x) m_ C +m_ O m_ C x=m_ O (r-x)m_ C x+m_ O x=m_ O rx= m_ O m_ C +m_ O r By substituting the values, we get Hence, position of centre of mass is 0.63 Å from carbon atom.