A metal ball of mass 2 kg moving with a velocity of 36 kmph has a head on collision with a stationary ball of mass 3 kg . After the collision, if both balls move together, the loss in kinetic energy due to collision is

Step-by-step solution

The linear momentum remains conserved before and after the collision, therefore, ⇒ 2   kg × 36 × 1000 3600   m   s - 1 + 3   kg × 0 = 3   kg + 2   kg v v = 20 5 = 4   m   s - 1 The loss in kinetic energy is, ∆ K E = K E i - K E f = 1 2 2   kg 10   m   s - 1 2 + 0 - 1 2 2   kg + 3   kg 4   m   s - 1 2 = 100 - 40 = 60   kg   m 2   s - 2   = 60   J