A bomb of mass (9 ~kg ) explodes into two pieces of mass (3 ~kg ) and (6 ~kg ). The velocity of mass (3 ~kg ) is (16 ~m / s ). The kinetic energy of mass (6 ~kg ) (in joule) is

Step-by-step solution

Given, mass of bomb, (M=9 ~kg ) According to conservation of linear momentum, ( aligned & M 0 & =m₁ v₁+m₂ v₂ & 9 0 & =3 16+6 v₂ & v₂ & = -3 16 6 =-8 ~m / s aligned ) ( ) Kinetic energy of mass, (m₂=6 ~kg ) (given) ( aligned K & = 1 2 m₂ v₂^2= 1 2 6 (-8)^2 & = 1 2 6 64=192 ~J aligned )