A particle of mass 4 M which is initially at rest explodes into three pieces of masses M , M and 2 M . The equal masses move along X and Y -axes with velocities 4 ~ms ⁻¹ and 6 ~ms ⁻¹ , respectively. The magnitude of the velocity of the heav

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A particle of mass 4 M which is initially at rest explodes into three pieces of masses M , M and 2 M . The equal masses move along X and Y -axes with velocities 4 ~ms ⁻¹ and 6 ~ms ⁻¹ , respectively. The magnitude of the velocity of the heavier mass is

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Correct answer: C. 13 ~ms ⁻¹

Initial mass of particle =4 M Initial velocity of particle =0 . After explosion into three pieces of masses M, M and 2 M particle of equal masses move along X and Y axes with velocities 4 ~m / s and 6 ~m / s , respectively. So, according to law of conservation of momentum mass 2 M particle will move in the direction shown in the figure. Law of conservation of momentum, Momentum before collision = Momentum after collision. array rlrl & & 4 M 0 & =2 M v +M v _x+M v _y & & -2 M v & =M ( v _x+ v _y ) & & -2 v & =4 i +6

A particle of mass 4 M which is initially at rest explodes into three pieces of masses M , M and 2 M . The equal masses move along X and Y -axes with velocities 4 ~ms ⁻¹ and 6 ~ms ⁻¹ , respectively. The magnitude of the velocity of the heavier mass is

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