A canon shell fired breaks into two equal parts at its highest point. If one part retraces the path to the canon with kinetic energy E₁ and kinetic energy of the second part is E₂ , then

Step-by-step solution

Momentum before explosion =u 2 ~m Momentum after explosion =-m u +m v₂ Momentum is conserved, so aligned & 2 m u =-m u +m v₂ & v₂=3 u aligned Kinetic energy of first part aligned & =E₁= 1 2 m v₁^2= 1 2 m(-u )^2 E₁ & = 1 2 m u^2 ^2 aligned Now, kinetic energy of second part =E₂= 1 2 m v₂^2=9 1 2 m u^2 ^2 =9 E₁ So, E₂=9 E₁