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AP EAMCET2015PhysicsCenter of Mass, Momentum and Collision

A ball P moving with a speed of v ~ms ⁻¹ collides directly with another identical ball Q moving with a speed 10 ~ms ⁻¹ in the opposite direction. P comes to rest after the collision. If the coefficient of restitution is 0.6 , the value of v is

Options

  1. A30 ms⁻¹
  2. B40 ms⁻¹
  3. C50 ms⁻¹
  4. D60 ms⁻¹

Correct answer

B. 40 ms⁻¹

Step-by-step solution

From conservation of moment, aligned & m(v-10)=m v₂ & v₂=(v-10) & V 10 m / s & V =0 ~V ₂ Berore aligned The coefficient of restitution, aligned e & = Velocity of separation Velocity of approach & = v₂-v₁ u₁+u₂ = (v-10)-0 (v+10) & 0.6= v-10 v+10 & 0.6 v+6=v-10 & 0.4 v=16 v=40 ~ms ⁻¹ aligned

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