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AP EAMCET2013PhysicsCenter of Mass, Momentum and Collision

A mass of 2.9 ~kg is suspended from a string of length 50 ~cm and is at rest. Another body of mass 100 ~g , which is moving horizontally with a velocity of 150 ~m / s strikes and sticks to it. Subsequently when the string makes an angle of 60^ with the vertical, the tension in the string is (g=10 ~m / s ^2 )

Options

  1. A145 N
  2. B135 N
  3. C125 N
  4. D90 N

Correct answer

B. 135 N

Step-by-step solution

From law of conservation of momentum, we known, array lc & m₁ u₁+m₂ u₂=m₁ v₁+m₂ v₂ u₁=0, u₂=150 ~m / s , m₁=2.9 ~kg and m₂=0.1 ~kg So, & 2.9 150=(2.9+0.1) v & 2.9 150 3 =v & Also, & T = m v^2 r array Putting the values and solving, we get T=135 ~N .

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