AP EAMCET2007PhysicsCenter of Mass, Momentum and Collision
In two separate collisions, the coefficient of restitutions e₁ and e₂ are in the ratio 3: 1 . In the first collision the relative velocity of approach is twice the relative velocity of separation, then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is
Options
- A1: 6
- B2: 3
- C3: 2
- D6: 1
Correct answer
D. 6: 1
Step-by-step solution
Coefficient of restitution is given by e= relative velocity of separation relative velocity of approach we have e₁= 1 2 and e₂= ( relative velocity of separation relative velocity of approach )₂ Given, e₁ e₂ = 3 1 e₂ e₁ = 1 3 ( relative velocity of separation relative velocity of approach )₂= 1 3 1 2 = 1 6 ( relative velocity of approach relative velocity of separation )₂= 6 1