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AP EAMCET2006PhysicsCenter of Mass, Momentum and Collision

A man of 50 ~kg is standing at one end on a boat of length 25 ~m and mass 200 ~kg . If he starts running and when he reaches the other end, he has a velocity 2 ~ms ⁻¹ with respect to the boat. The final velocity of the boat is : (in ms ⁻¹ )

Options

  1. A2 5
  2. B2 3
  3. C8 5
  4. D8 3

Correct answer

A. 2 5

Step-by-step solution

Let v be the velocity of the boat with respect to the water, then from conservation of linear momentum. (200+50) v+50 2=50 0+200 0250 v=-100v=- 100 250 =- 2 5 ~m / s

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