Photoelectrons are emitted with maximum velocity v when light of frequency 3 f incidents on a photosensitive material of work function 2 hf . If the frequency of the incident light is 4.25 f , the maximum velocity of the emitted photoelectrons is (h-Plank's constant)

Step-by-step solution

Initial frequency, f₁=3 f Initial velocity v ₁= v Work function =2 hf final frequency, f ₂=4.25 f final velocity, v ₂= ? Kinetic energy is given as, K E=h f- 1 2 mv ₁^2=3 hf -2 hf = hf m= 2 h f v^2 final kinetic energy, aligned & 1 2 mv ^2=4.25 hf -2 hf & =2.25 hf aligned aligned & 1 2 2 h f v^2 v₂^2= 225 100 & v₂^2 v^2 = 225 100 & v₂^2= 225 100 v^2= ( 15 10 v )^2 & v₂=1.5 v aligned