AP EAMCET20227 Jul 2022Morning ShiftPhysicsDual Nature of MatterActual
A bulb of power 660 ~W radiates uniformly in all directions. The pressure exerted by the radiation on the surface at a distance of 5 ~m is
Options
- A5 10⁻⁸ ~Pa
- B2 10⁻⁹ ~Pa
- C7 10⁻⁹ ~Pa
- D3 10⁻⁸ ~Pa
Correct answer
C. 7 10⁻⁹ ~Pa
Step-by-step solution
Radiation pressure on a surface at a distance r from a bulb of power P is gives as, Radiation pressure = P 4 r^2 c (for perfectly absorbing surface) Here, P=660 ~W , r=5 ~m , c=3 10^8 ~m / s So, radiation pressure = 660 4 5^2 3 10^8 =7 10⁻⁹ ~Pa