The de Broglie wavelength associated with a proton under the influence of an electric potential of 100 volts is

Step-by-step solution

From the conservation of energy, 1 2 m v 2 = e V ⇒ p 2 2 m = e V ⇒ p 2 = 2 m e V ⇒ p = 2 m e V Wavelength, λ = h p ⇒ λ = h 2 m e V ⇒ λ = 6 . 625 × 10 - 34 2 × 1 . 67 × 10 - 27 × 1 . 6 × 10 - 19 × 100 ⇒ λ = 6 . 625 × 10 - 34 2 × 1 . 67 × 10 - 27 × 1 . 6 × 10 - 19 × 100 ⇒ λ = 2 . 86   pm