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AP EAMCET201823 Apr 2018Morning ShiftPhysicsDual Nature of MatterActual

An -particle and a proton are accelerated from rest by the same potential, then the ratio of their de-Broglie wavelength is

Options

  1. A2 2 : 1
  2. B1: 2 2
  3. C1 : 2
  4. D2 : 1

Correct answer

B. 1: 2 2

Step-by-step solution

de-Broglie's wavelength, = h p = h 2 m E = h 2 m e V The particles are at same potential, so _ _p = h / 2 m_ e_ V h / 2 m_p e_p V Mass of -particle =4 times mass of proton. Charge of -particle =2 times charge of proton. So, _ _p = m_p e_p 4 m_p 2 e_p = 1 2 2

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