Two photons of energy 2.5 eV and 3.5 eV fall on a metal surface of work function 1.5 eV . The ratio of the maximum velocities of the photoelectrons emitted from the metal surface is

Step-by-step solution

Using, the equation Dividing Eq. (i) by Eq. (ii) we get aligned & 1 2 m v₁^2 1 2 m v₂^2 = h v_ 0₁ - ₀ h v_ 0₂ - ₀ & v₁^2 v₂^2 = (2.5-1.5) (3.5-1.5) = 1 2 & v₁^2 v₂^2 = 1 2 or v₁ v₂ = 1 2 aligned