A mixture of gasses consists of 16 ~g of Helium and 16 ~g of Oxygen. The ratio of specific heats of the mixture is nearly

Step-by-step solution

Helium mass, m_H=16 g oxygen mass, m_o=16 ~g let, M _ o = molar mass of oxygen M _ H = molar mass of Helium Number of moles of oxygen, n _ o = m _ o M _ o = 16 32 = 1 2 No. of moles of Helium, n _ h = M _ h M _ h = 16 4 =4 aligned & C _ v ₁ = Specific heat of oxygen at constant volume, & C _ v ₁ = 5 2 R & C _ v ₂ = specific heat of Helium at constant volume, & C _ v ₂ = 3 2 R aligned Specific heat of mixture at constant volume, aligned & C _ v = n _ o C _ v ₁ + n _ h C _ v ₂ n _ o + n _ h = 1 2 5 2 R +4 3 2 R 1 2 +