AP EAMCET202317 May 2023Evening ShiftPhysicsKinetic Theory of GasesActual
If the average kinetic energy of a gas molecule at 27^ C is 3.3 10⁻²⁰ ~J , then the average kinetic energy of the gas molecules at 127^ C is
Options
- A15 10⁻²⁰ ~J
- B0.68 10⁻²⁰ ~J
- C4.4 10⁻²⁰ ~J
- D10.3 10⁻²¹ ~J
Correct answer
C. 4.4 10⁻²⁰ ~J
Step-by-step solution
Average kinetic energy of a gas is given by aligned & E= 1 2 K T & E₂ E₁ = T₂ T₁ E₂= T₂ E₁ T₁ & = (127+273) 3.3 10⁻²⁰ (27+273) & = 400 3.3 10⁻²⁰ 300 =4.4 10⁻²⁰ J aligned