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AP EAMCET20224 Jul 2022Evening ShiftPhysicsKinetic Theory of GasesActual

In non-rigid diatomic molecule with an additional vibrational mode

Options

  1. A81 C v 2 = 49 C P 2
  2. B49 C v 2 = 25 C P 2
  3. C49 C v 2 = 81 C P 2
  4. D25 C v 2 = 49 C p 2

Correct answer

A. 81 C v 2 = 49 C P 2

Step-by-step solution

In non-rigid diatomic molecule with an additional vibrational mode, total degree of freedom f = 3 rotational + 3 translational + 1 vibrational = 7 Therefore, C p C v = 1 + 2 f = 9 7 ⇒ 81 C v 2 = 49 C P 2

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