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AP EAMCET202017 Sep 2020Evening ShiftPhysicsKinetic Theory of GasesActual

The ratio of specific heats at constant pressure and at constant volume is ( ). To find out the degree of freedom, the expression is

Options

  1. A(f= 2 -1 )
  2. B(f= +1 2 )
  3. C(f= 2 +1 )
  4. D(f= 1 +1 )

Correct answer

A. (f= 2 -1 )

Step-by-step solution

We know that, ( = C_p C_V ) ...(i) Energy of (N ) molecules of gas, (U= f 2 R T ) where, (f ) is degree of freedom. ( array ll & C_V= d U d T = d d T ( f 2 R T )= f R 2 & C_p=C_V+R= f R 2 +R C_p= (f+2) R 2 array ) ( ) From Eq. (i), we get ( gathered = (f+2) R / 2 f R / 2 = f+2 f f -f=2 f( -1)=2 f= 2 -1 gathered )

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