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AP EAMCET202420 May 2024Morning ShiftPhysicsLaws of MotionActual

A 4kg mass is suspended as shown in figure. All pulleys are frictionless and spring constant K is 8 10^3 Nm ⁻¹ The extension in spring is ( g =10 ~ms ⁻² )

Options

  1. A2 mm
  2. B2 cm
  3. C4 cm
  4. D4 mm

Correct answer

B. 2 cm

Step-by-step solution

k =8 10^3 Nm ⁻¹ From figure, T=40 ~N Force in spring, F =4 ~T =160 ~N Extension in the spring, x= F K = 160 8 10^3 =2 ~cm

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