Three blocks of masses 2 ~m , 4 ~m and 6 m are placed as shown in figure. If 37^ = 3 5 , 53^ = 4 5 the acceleration of the system is

Step-by-step solution

aligned & F_ n e t =(2 m+4 m+6 m) a & 10 mg 53^ -2 mg 37^ =12 ma aligned aligned & a = (10 4 5 -2 3 5 ) g 12 & a = 17 30 ~g aligned