A bullet of mass 20 ~g moving with 500 ~ms ⁻¹ is pierced 1 ~cm into a wooden block, then the retarding force experienced by the bullet is

Step-by-step solution

Mass, m =20 ~g =20 10⁻³ ~kg velocity, u =500 ~m / s distance, d =1 ~cm =0.0 / m final velocity, v=0 Using Equation of Motion, v^2-u^2=2 a d aligned & -(500)^2=2 a 0.01 & a =- 500 50000 2 0.01 =-1.25 10^7 ~m / s ^2 aligned using newton's second law, aligned & F = ma & F =20 10⁻³ 1.25 10^7 & ~F =250 10^3 ~N aligned