A body of mass 1 ~kg is moving with a velocity 10 ~ms ⁻¹ due to a constant force on a horizontal rough surface having coefficient of kinetic friction 0.4 . If the constant force is removed, the body comes to rest in a time (Acceleration due to gravity =10 ~ms ⁻² )

Step-by-step solution

Mass of body, m =1 ~kg velocity, v=10 ~m / s Coefficient of kinetic friction, =0.4 from the equation of motion aligned & v = u + at & t = v a ( F = mg ) & = vm F = vm mg = v g aligned The body comes to rest in a time t = v g = 10 0.4 10 =2.5 ~s