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AP EAMCET202315 May 2023Evening ShiftPhysicsLaws of MotionActual

A block of mass 5 ~kg moving on a rough surface with a velocity of 4 ~ms ⁻¹ is stopped by the friction in 2 seconds. Then the coefficient of friction between the contact surfaces is (Acceleration due to gravity =10 ~ms ⁻² )

Options

  1. A0.4
  2. B0.3
  3. C0.5
  4. D0.2

Correct answer

D. 0.2

Step-by-step solution

Mass of block, m =5 ~kg velocity v =4 ~m / s aligned & F = mg ma = mg & mv t = mg = v gt = 4 2 10 =0.2 aligned

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