A body is travelling with 10 ~ms ⁻¹ on a rough horizontal surface. It's velocity after 2 ~s is 4 ~ms ⁻¹ . The coefficient of kinetic friction between the block and the plane is (acceleration due to gravity =10 ~ms ⁻² )

Step-by-step solution

Initial speed of body on the horizontal rough surfaces, u=10 ~ms ⁻¹ Final velocity, v=4 ~ms ⁻¹ and t=2 ~s . If a be the retardation due to friction, then by using equation, v=u-a t 4=10-a 2 2 a=6 a=3 ~ms ⁻² According to given situation, friction force =m a aligned & _k m g=m a & _k= a g = 3 10 =0.3 aligned