A cricket ball of mass 50 g having velocity 50 cm s - 1 is stopped in 0 . 5 s . The force applied to stop the ball is

Step-by-step solution

Initial momentum of the ball is = 50 × 10 - 3   kg × 50 × 10 - 2   m   s - 1 = 25 × 10 - 3   kg   m   s - 1   Final momentum = 0   kg   m   s - 1   Magnitude of force applied = ∆ p t = 0   kg   m   s - 1 - 25 × 10 - 3   kg   m   s - 1   0 . 5   s = - 5 × 10 - 2   kg   m   s - 1 = 0 . 05   N