AP EAMCET202124 Aug 2021Morning ShiftPhysicsLaws of MotionActual
What is the angle of banking of a railway track of radius of curvature 250 ~m , if the maximum velocity of the train is 90 ~km / h ? (g=10 ~ms ⁻² )
Options
- A= ⁻¹ ( 1 2 )
- B= ⁻¹ ( 1 3 )
- C= ⁻¹ ( 1 4 )
- D= ⁻¹ ( 1 5 )
Correct answer
C. = ⁻¹ ( 1 4 )
Step-by-step solution
Given, radius of curvature, r=250 ~m Maximum velocity of train, v=90 kmh ⁻¹ = 90 5 18 ~m / s =25 ~m / s Let be the angle of banking of railway track. Then, by using an expression of maximum safe speed, v₂=r g = v^2 r g By substituting the values, we get aligned & = (25)^2 250 10 = 625 2500 = 1 4 & = ⁻¹ ( 1 4 ) aligned