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AP EAMCET202123 Aug 2021Evening ShiftPhysicsLaws of MotionActual

A block B , lying on a table, weights w . The coefficient of static friction between the block and the table is . Assume that, the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

Options

  1. Aw
  2. Bw
  3. Cw 1+ ^2
  4. Dw

Correct answer

B. w

Step-by-step solution

Given that, weight of block B=w Coefficient of friction between block and table = Let the maximum weight of block A=w_A To keep the cord between block B and knot horizontal, block must remains in equilibrium. Now, from FBD of knot and block B , we get w_A=T ...(i) and f= w=T ...(ii) By dividing Eq. (i) by Eq. (ii), we get aligned w_A w & = T T w_A & = w aligned

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