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AP EAMCET202022 Sep 2020Morning ShiftPhysicsLaws of MotionActual

A block P of mass M_P is in contact with another block Q of mass M_Q as shown in the fígure and they are placed on a smooth floor. Force on block Qis

Options

  1. AM_p M_p+M_Q
  2. BM_Q F M_p+M_Q
  3. CM_ F M_Q
  4. DM_Q F M_p

Correct answer

B. M_Q F M_p+M_Q

Step-by-step solution

If a be the common acceleration of system of blocks on application of force F . Free body diagram of block P and Q are given as Hence, for block P, F-R=M_P a For block Q, R=M_Q a Adding Eqs. (i) and (ii), we get F= (M_P+M_Q ) a M_P+M_Q Force on block Q is given as R=M_Q a=M_Q F M_P+M_Q = M_Q F M_P+M_Q

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