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AP EAMCET202021 Sep 2020Evening ShiftPhysicsLaws of MotionActual

A block of mass (m ) is placed on a smooth wedge of inclination ( ). The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block ( (g ) is acceleration due to gravity) will be

Options

  1. A(m g )
  2. B(m g )
  3. C(m g )
  4. D(m g )

Correct answer

D. (m g )

Step-by-step solution

The given situation is shown in the following figure, The acceleration given to wedge to the left is (a ). The block has a pseudo acceleration to the right, pressing against the wedge because of which the block does not move. In this case, ( array ll & m g =m a & a= g (i) array ) Force exerted by the wedge on the block is equal to normal reaction on the block, ( aligned i.e. R & =m g +m a & =m g +m g [From Eq. (i)] & = m g [ ^2 + ^2 ] R & = m g =m g aligned )

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