A block of mass 48 kg kept on a smooth horizontal surface is pulled by a rope of length 4 m by a horizontal force of 25 N applied to the other end. If the linear density of the rope is 0 . 5 kg m - 1 , the force acting on the block is

Step-by-step solution

Given, Mass of block M = 48   kg Linear density of string λ = 0 . 5   kg   m - 1 Length of string l = 4   m Force applied F = 25   N Total mass of the system m = M + λ l = 50   N Net acceleration of system a sys = F m = 25 50 = 0 . 5   m   s - 1 Suppose Tension at a point connecting end of string with block is T . From the F . B . D . of block- ⇒     T = M a sys = 48 × 0 . 5 ⇒     T = 24   N Hence, force acting on the block