Two blocks A and B of masses 1 . 5 kg and 0 . 5 kg respectively are connected by a massless inextensible string passing over a frictionless pulley as shown in the figure. Block A is lifted until block B touches the ground and then block A is released. The initial height of block A is 80 cm when block B just touches the ground. The maximum height reached by block B from the ground after the block A falls on the ground

Step-by-step solution

Common acceleration of the system is given by- a sys = 1 . 5 - 0 . 5 1 . 5 + 0 . 5   g = g 2 = 5   m   s - 2 When block of mass 1 . 5   kg hits the ground, at that time block of mass 0 . 5   kg will be at a height of 80   cm from the ground. After this point string become slack and block B will move with deceleration g = 10   m   s - 2 . Using third equation of motion, speed of block B , When block A Reaches the ground- v 2 = 0 + 2   g 2   80 100 = 8 ⇒