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AP EAMCET201921 Apr 2019Morning ShiftPhysicsLaws of MotionActual

A block of mass m is lying on a rough inclined plane having an inclination = ⁻¹ ( 1 5 ) . The inclined plane is moving horizontally with a constant acceleration of a=2 ~ms ⁻² as shown in the figure. The minimum value of coefficient of friction, so that the block remains stationary with respect to the inclined plane is (Take, g=10 ~ms ⁻² )

Options

  1. A2 9
  2. B5 12
  3. C1 5
  4. D2 5

Correct answer

B. 5 12

Step-by-step solution

The block-plane system is shown in the figure, So, from the above free body diagram (FBD), downward acceleration, Divided the Eq. (iii) by and putting the values, aligned & = 10+2 1 10 1 -2 = 10+2 5 10 5-2 & = 20 48 = 5 12 aligned Hence, the correct option is (b).

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