AP EAMCET201824 Apr 2018Morning ShiftPhysicsLaws of MotionActual
One end of a light string is fixed to a clamp on the ground and the other end passes over a fixed frictionless pulley as shown in the figure. It makes an angle of 30^ with the ground. The clamp can tolerate a vertical force of 40 ~N . If a monkey of mass 5 ~kg were to climb up the rope, then the maximum acceleration in the upward direction with which it can climb safely is (g=10 ~ms ⁻² )
Options
- A2 ~ms ⁻²
- B4 ~ms ⁻²
- C6 ~ms ⁻²
- D8 ~ms ⁻²
Correct answer
C. 6 ~ms ⁻²
Step-by-step solution
Let T is tension in the string. Maximum vertical force on clamp, T 30^ =40 array lrl & T 1 2 =40 & T=80 ~N array Let maximum acceleration of monkey for sate climbing is a . Then, FBD of monkey aligned & T-m g=m a a= T-m g m & a= 80-5 10 5 a= & 6 ~m / s ^2 aligned