AP EAMCET2007PhysicsLaws of Motion
A man slides down on a telegraphic pole with an acceleration equal to one-fourth of acceleration due to gravity. The frictional force between man and pole is equal to in terms of man's weight w
Options
- Aw 4
- Bw 2
- C3 w 4
- Dw
Correct answer
C. 3 w 4
Step-by-step solution
Man is sliding down the telegraphic pole with acceleration g / 4 . So, array rlrl & m g-F & = m g 4 & & F & =m g- m g 4 & F & = 3 m g 4 & & F & = 3 w 4 array